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Graph the system below and write it solutions(2x + y = -4(y= -1/2x + 2

User Rachida
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Graphing a system of equations

We will choose two points, when x=0 and when x=1, so we can graph two points for each line

First point: when x = 0

2x + y = -4

2 · 0 + y = -4

0 + y = -4

y = -4

(0, -4)

y = -1/2x + 2

y = -1/2 · 0 + 2

y = 0 + 2

y = 2

(0, 2)

Second point: when x=1

2x + y = -4

2 · 1 + y = -4

2 + y = -4

y = -4 - 2

y = -6

(1, -6)

y= -1/2x + 2

y= -1/2 + 2​

y = 3/2

(1, 3/2)

We draw a line that passes through the pair of points of the first equation:

(0, -4) and (1, -6)

and the pair of points of the second:

(0, 2) and (1, 3/2)

Finding the solution

We know that the solution is given by the intersect of the two lines,

We can observe that they intersect each other at the point x = -4 and y = 4

The solution is x=-4 and y=4: (-4, 4)

Graph the system below and write it solutions(2x + y = -4(y= -1/2x + 2-example-1
Graph the system below and write it solutions(2x + y = -4(y= -1/2x + 2-example-2
Graph the system below and write it solutions(2x + y = -4(y= -1/2x + 2-example-3
Graph the system below and write it solutions(2x + y = -4(y= -1/2x + 2-example-4
User Nabmeister
by
5.3k points
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