Answer:
35
Explanation:
This is a combination problem therefore we need to use the combination formula using factorials, plug in the values for n and r which would be 7 since there are 7 individuals in the group and 3 because we are making outcomes of 3.
C(n,r)=C(7,3)
=7!(3!(7−3)!)
=7!3!×4!
= 35
Finally, we can see that the total number of possible outcomes is 35