Question

3000.0 J of thermal energy is added to a 250.0 g block of metal and thetemperature is increased by 37.5 °C. Based on the values in the followingtable of specific heats, which is the most likely identity of this metal

Answer 1

`\begin{gathered} \text{ The specific heat of the metal block is 0.32 J/g}\degree C \\ \text{ The metal is Germanium} \end{gathered}`

Step-by-step explanation

Given information

The thermal energy added is 3000 J

The mass of the metal block is 250.0 grams

The temperature change is 37.5 degrees Celcius

Firstly, we need to find the specific heat capacity of the metal block

To find the specific heat capacity of the metal block, follow the steps below

Step 1: Write the formula for calculating the heat of a substance

`\begin{gathered} \text{ q = mc}\Delta\theta \\ \text{ Where} \\ q\text{ = heat energy} \\ m\text{ = mass} \\ c\text{ = specific heat capacity} \\ \Delta\theta=\text{ increase in temperature} \end{gathered}`

Step 2: Substitute the given data into the formula in step 1 to find c

`\begin{gathered} q\text{ = mc}\Delta\theta \\ \text{ make c the subject of the formula} \\ \text{ c = }(q)/(m\Delta\theta) \\ \text{ c = }\frac{3000}{250\text{ }*37.5} \\ c\text{ = }(3000)/(9375) \\ c\text{ = 0.32 J/g}\degree C \end{gathered}`

Hence, the specific heat capacity of the metal block is 0.32 J/g degrees Celcius

According to the table of specific heats, the metal that has the above specific heats is Germanium