Paralell to line x + 3y = 15
Passes through (6, 1)
First we have to write the line equation in the form y = mx + b to know the slope:
x + 3y = 15
3y = -x + 15
y = (-x + 15)/3 = (-1/3)x + 5
y = (-1/3)x + 5
Therefor the slope is (-1/3)
The equation of the line would be: y = (-1/3)x + b, and since it passes throug (6,1), we can use these values to fin b:
y = (-1/3)x + b
1 = (-1/3)6 + b
1 = -2 + b
1 + 2 = b
b = 3
So the equation we are looking for is y = (-1/3)x + 3
Answer:
y = (-1/3)x + 3