To answer this question we will use the following slope-point formula for the equation of a line:
![y-y_1=m(x-x_1)\text{.}](https://img.qammunity.org/2023/formulas/mathematics/college/50rdws8olj8e9mrccwea6tp7o8rrt3xm71.png)
Recall that two lines are parallel if they have the same slope.
Now, notice that the given equation is y=5x, therefore, the slope of the given equation is 5.
Using the slope-point formula, we get that the equation of the parallel line to y=5x that passes through (-5,5) is:
![y-5=5(x-(-5))\text{.}](https://img.qammunity.org/2023/formulas/mathematics/college/wnskdlebk2l4se6h4ikhemv4h9iq7opmt5.png)
Simplifying the above equation we get:
![\begin{gathered} y-5=5(x+5), \\ y-5=5x+25. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4eeai8laa2nargwweweczhw7u23khey2bh.png)
Adding 5 to the above equation we get:
![\begin{gathered} y-5+5=5x+25+5, \\ y=5x+30. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/or52doi18n21orn58uo5ep46amkxig331k.png)
Answer:
![y=5x+30.](https://img.qammunity.org/2023/formulas/mathematics/college/fsadk7cu79xs1gqm2gkb02oytex4l2zpzt.png)