215k views
3 votes
Find an equation for the line with the given properties. Express your answer using either the general form or the slope-intercept form of the equation of a line.Parallel to the line y=5x containing the points (-5,5)

User Ver
by
8.0k points

1 Answer

2 votes

To answer this question we will use the following slope-point formula for the equation of a line:


y-y_1=m(x-x_1)\text{.}

Recall that two lines are parallel if they have the same slope.

Now, notice that the given equation is y=5x, therefore, the slope of the given equation is 5.

Using the slope-point formula, we get that the equation of the parallel line to y=5x that passes through (-5,5) is:


y-5=5(x-(-5))\text{.}

Simplifying the above equation we get:


\begin{gathered} y-5=5(x+5), \\ y-5=5x+25. \end{gathered}

Adding 5 to the above equation we get:


\begin{gathered} y-5+5=5x+25+5, \\ y=5x+30. \end{gathered}

Answer:


y=5x+30.

User Troubadour
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories