Question

Question 9 of 18SubmitWhat is the specific heat of a 54.51 g piece of anunknown metal that exhibits a 45.2°C temperature changeupon absorbing 1870 J of heat?

Answer 1

`\text{ 0.76 J/g.\degree C}`

Step-by-step explanation:

Here, we want to calculate the specific heat capacity of the metal

Mathematically:

`Q\text{ = mc}\Delta T`

where :

Q is the amount of heat absorbed given as 1870 J

m is the mass of the metal given as 54.51g

c is the specific heat capacity that we want to calculate

delta T is the temperature change given as 45.2 °C

Rewriting the formula above in terms of c, we have it that:

`c\text{ = }(Q)/(m\Delta T)`

Substituting the values, we have it that:

`c\text{ = }(1870)/(54.51*45.2)\text{ = 0.76 J/g.\degree C}`