Question

I need help with this problem I been stuck on it for hours

Answer 1

The average rate of change of height is

`(\Delta H)/(\Delta t)`

(a).

From 0 seconds to 2.3 seconds

`\Delta t=2.3s-0s=2.3s`

and

`\Delta H=92m-0m=92m`

Therefore,

`(\Delta H)/(\Delta t)=(92m)/(2.3s)=\textcolor{#FF7968}{(40m)/(s)}`

(b).

From 4.6 seconds to 11.5 seconds we have

`\Delta t=11.5s-4.6s=6.9s`

and

`\Delta H=0m-138m=-138m`

Therefore,

`(\Delta H)/(\Delta t)=(-138m)/(6.9s)=\textcolor{#FF7968}{(-20m)/(s)}`

Hence, (a). 40m/s and (b). -20m/s.