The given expression is

First, let's move all the terms to the left side

Then, we reduce like terms

To find the x-intercepts, we use the quadratic formula
![x_(1,2)=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/li72dimqx1poek8bdg3bs589861h83kfxl.png)
Where a = 1, b = -1, and c = -3. Let's replace these values
![\begin{gathered} x_(1,2)=\frac{-(-1)\pm\sqrt[]{(-1)^2-4(1)(-3)}}{2(1)}_{} \\ x_(1,2)=\frac{1\pm\sqrt[]{1+12}}{2}=\frac{1\pm\sqrt[]{13}}{2} \\ x_1=\frac{1+\sqrt[]{13}}{2}\approx2.3 \\ x_2=\frac{1-\sqrt[]{13}}{2}\approx-1.3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/43lj8n1od7mlpjxbr3bdx0cnsiszztc73t.png)
Hence, the x-intercepts are (2.3, 0) and (-1.3, 0).