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14. Find the value of x. Round to the nearest tenth(4 points).X(legi)2 + (leg2)2 = (hypotenuse)2 4m6 m

14. Find the value of x. Round to the nearest tenth(4 points).X(legi)2 + (leg2)2 = (hypotenuse-example-1
User Byte Brad
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1 Answer

6 votes

To find x, we have to use Pythagorean's Theorem.


(hip)^2=(leg_1)^2+(leg_2)^2

Let's replace each of them.


x^2=4^2+6^2

Let's solve for x.


\begin{gathered} x=\sqrt[]{16+36} \\ x=\sqrt[]{52}\approx7.2 \end{gathered}

Therefore, x is 7.2, approximately.

User Mojoblanco
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