Lifting an elevator 12 m requires 70.0 kj. If doing so takes 16.5 s, what is the average power of the elevator during the process?

asked Nov 9, 2023 189k views

4 votes

by APD

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4 votes

Answer:

See below

Step-by-step explanation:

power = work / time = 70 000 j / 16.5 s = 4242 w

Alefteris answered Nov 14, 2023

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