Hello there. To solve this question, we have to remember some properties about conjugates and real (complex) numbers.
Suppose the expression
![y+3](https://img.qammunity.org/2023/formulas/mathematics/high-school/jdlc92igjiu8ey0hbimq06vlpti4o1129n.png)
Is a real number, hence we know that
![y](https://img.qammunity.org/2023/formulas/mathematics/high-school/39evgwyfztrxf0jqm5m4q20wdsbwaeh9qb.png)
must also be a real number because the real numbers are a field and they are closed under addition.
The conjugate of a real number is then the real number itself, which means that
![\overline{y+3}=y+3](https://img.qammunity.org/2023/formulas/mathematics/high-school/w95561gz923btd40vdmbw8fbfhi40ufhxu.png)
Otherwise, if y is a complex number, it means it's imaginary part is not equal to zero.
Assuming y = a + bi for a, b real numbers and b not equal to zero, we have that
![y+3=a+bi+3=(a+3)+bi](https://img.qammunity.org/2023/formulas/mathematics/high-school/jq4nq5xd1f8j0kopwlrzfviov31rk1vk7c.png)
Hence the conjugate of this number is
![\overline{(a+3)+bi}=(a+3)-bi](https://img.qammunity.org/2023/formulas/mathematics/high-school/o3opbpczhaik2wjtxeycnazgmsp27myxlo.png)
That is equivalent to have
![\overline{y}+3](https://img.qammunity.org/2023/formulas/mathematics/high-school/a7lerx08d8edfsgzeyrlaxu0hxq48nqjt1.png)
If y is a complex number.