Evaluate : 9⁴xa⁷b⁴/3⁵xa⁴b⁴

asked Aug 16, 2023 105k views

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$(9^4\cdot xa^7\cdot b^4)/(3^5\cdot xa^4\cdot b^4)$
9^4=3^8

$(3^8\cdot xa^7\cdot b^4)/(3^5\cdot xa^4\cdot b^4)$
$3^{8\text{ - 5}}\cdot a^{7\text{ - 4}}$
$3^3\cdot a^3\text{ }\Rightarrow27a^3$

Huczilla answered Aug 22, 2023

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