Answer:
Hello your question is poorly written attached below is the complete question
answer :
1) 60 kHz
2) Tmax = ( 1 / 34000 ) secs
Step-by-step explanation:
1) Determine the Nyquist sampling frequency, (in kHz), for the input signal.
F(s) = 2 * Fmax
Fmax = 30 kHz ( since Xa(t) is band limited to 30 kHz )
∴ Nyquist sampling frequency ( F(s) ) = 2 * 30 = 60 kHz
2) Determine the largest sampling period (in s) .
Nyquist sampling period = 1 / Fs = ( 1 / 60000 ) s
but there is some aliasing of the input signal ( minimum aliasing frequency > cutoff frequency of filter ) hence we will use the relationship below
= 2π - 2π * T * 30kHz ≥ 2π * T * 4kHz
∴ T ≤
largest sampling period ( Tmax ) = ( 1 / 34000 ) secs