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I solved the first one but I can’t figure out the second one

I solved the first one but I can’t figure out the second one-example-1

1 Answer

4 votes

Answer:


\begin{gathered} (h\circ k)(3)=3 \\ (k\circ h)(-4b)=-4b \end{gathered}

Step-by-step explanation:

We need to use the definition for a composition of functions and inverse functions.

If h and k are inverse functions:


(k\circ h)(x)=(h\circ k)(x)=x

Then, the composition of two inverse functions give us the input (x, in the definition above).

Thus:


\begin{gathered} (h\circ k)(3)=3 \\ (k\circ h)(-4b)=-4b \end{gathered}

User Aaron Goldman
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