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Find the Perfect Square Trinomial of. y^2 + 1/2y = -1\16

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\begin{gathered} (y\text{ + }(1)/(4))(y\text{ + }(1)/(4)) \\ \\ y\text{ = -}(1)/(4)\text{ twice} \end{gathered}

To find the perfect square trinomial, we proceed as follows;


\begin{gathered} y^2\text{ + }(1)/(2)y\text{ = -}(1)/(16) \\ \\ y^2\text{ + }(1)/(2)y\text{ + }(1)/(16)\text{ = 0} \\ \\ y^2\text{ + }(1)/(2)y\text{ + (}(1)/(4))^2\text{ = 0} \\ \\ =(\text{ y + }(1)/(4))^2\text{ = 0} \\ \\ (y\text{ + }(1)/(4))(y\text{ + }(1)/(4))\text{ = 0} \\ \\ y\text{ = -}(1)/(4)\text{ twice} \end{gathered}

User Sumitkumar Dhule
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