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2. The height of a falling object with an initial velocity of a 49 ft/sec launched straightupward from the ground is given by h(t) = -16t2 + 49t where t is a time in seconds.Find the average rate of change
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2. The height of a falling object with an initial velocity of a 49 ft/sec launched straightupward from the ground is given by h(t) = -16t2 + 49t where t is a time in seconds.Find the average rate of change of the height from t = 1 to t = 2.

User Ajit Bhandari
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The formula for the average rate of change is the following

2. The height of a falling object with an initial velocity of a 49 ft/sec launched-example-1
2. The height of a falling object with an initial velocity of a 49 ft/sec launched-example-2
2. The height of a falling object with an initial velocity of a 49 ft/sec launched-example-3
User Tinonetic
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