Register
2. The height of a falling object with an initial velocity of a 49 ft/sec launched straightupward from the ground is given by h(t) = -16t2 + 49t where t is a time in seconds.Find the average rate of change
2.3k views
0 votes
2. The height of a falling object with an initial velocity of a 49 ft/sec launched straightupward from the ground is given by h(t) = -16t2 + 49t where t is a time in seconds.Find the average rate of change of the height from t = 1 to t = 2.

User Ajit Bhandari
by
4.2k points

1 Answer

5 votes

The formula for the average rate of change is the following

2. The height of a falling object with an initial velocity of a 49 ft/sec launched-example-1
2. The height of a falling object with an initial velocity of a 49 ft/sec launched-example-2
2. The height of a falling object with an initial velocity of a 49 ft/sec launched-example-3
User Tinonetic
by
4.4k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.5m questions

5.9m answers

Other Questions

I really need help!!!
Help, I really need help and I've been stuck on this one ^^^
Jay earns $50 per week plus $5.25 fro each hour worked in a given week Fred earnings are calculated using the formula p=6.25(x+8) where x is the number of hours Matt worked which statement is true. a.
Find the most important variable in the problem. A rower of a canoe row at a rate of 5 miles per hour in calm water. With the current, she can row 14 miles in the same time it takes her to tow 6 miles
9 2/3 × 6/7 = 2 3/4 × 5/6= 3 1/4 × 1/3= 3 2/3 × 2/3= 6 1/6 × 1/2=
Link Copied!