Question

7. A Jar contains 26 marbles. It has 10 red, 8 black and 8 green marbles. Two marbles are drawn, the first is not returned before the second one is drawn. What is the probability thatboth marbles are green?OP(Both Green) -OP(Both Green) -OP(Both Green) -OP(Both Green) - 1

Answer 1

Given:

The total number of marbles are 26.

Red marbles=10

Black marbles=8

Green marbles=8

The two marbles are drawn randomly,

To find the probability that both marbles are green,

The probability that first marbles chosen is green,

`\begin{gathered} P=\frac{desired\text{ outcomes}}{\text{Total outcomes}} \\ P=(8)/(26) \end{gathered}`

Condition is given that the first is not returned before the second one is drawn.

Now the we have 7 green marbles and total marbles are 25.

Probability is given by,

`P=(7)/(25)`

The total probability of getting both green marbles without replacement is,

`\begin{gathered} P=(8)/(26)*(7)/(25) \\ P=(4)/(13)*(7)/(25) \\ P=0.08615 \end{gathered}`

Answer: Probability is 0.08615.