Question

Can someone really help me and not mess around and help.

Answer 1

Data:

Scale factor: 1/4

`F^(\prime)(1,-(3)/(2)),I^(\prime)(2,-1),P^(\prime)(1,2)`

To find the coordinates of vertices of trianlge FIP you divide into the scale factor each ordered pair of F'I'P', as follow:

Division of fractions:

`((a)/(b))/((c)/(d))=(a\cdot d)/(b\cdot c)`

For F:

`\begin{gathered} F=(F^(\prime))/((1)/(4)) \\ \\ F((1)/((1)/(4)),(-(3)/(2))/((1)/(4)))=F(4,-(12)/(2))=F(4,-6) \end{gathered}`

For I:

`\begin{gathered} I=(I^(\prime))/((1)/(4)) \\ \\ I((2)/((1)/(4)),(-1)/((1)/(4)))=I(8,-4) \end{gathered}`

For P:

`\begin{gathered} P=(P^(\prime))/((1)/(4)) \\ \\ P((1)/((1)/(4)),(2)/((1)/(4)))=P(4,8) \end{gathered}`Then you have the next coordinates for FIP:
`F(4,-6),I(8,-4),P(4,8)`