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An object moving at a constant velocity of 5.4 m/s travels for 12 s. How far will it move during that time?x = xo + vo t + ½ a t 2 g = 9.8 m/s2 (downward)

User Nyavro
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An object moving at a constant velocity of 5.4 m/s travels for 12 s.

How far will it move during that time?

Recall that the velocity, distance, and time are related as


\begin{gathered} v=(s)/(t) \\ s=v\cdot t \end{gathered}

Where s is the horizontal distance, v is the velocity, and t is the time.

Let us substitute the given values and find the distance (s)


\begin{gathered} s=5.4\cdot12 \\ s=64.8\; m \end{gathered}

Therefore, the object will move 64.8 m during 12 s.

User Wmil
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