Question

12. Find the area of the region shown by dividing it into two trapezoids.271371812a.c.810sq.units546sq.units540sq.units1092 sq. unitsb.d.

Answer 1

The area of the region is the sum of the two trapezoids

Area of the trapezoid to the left :

`\begin{gathered} \text{Area}=(1)/(2)(a+b)** h \\ \text{Area}=(1)/(2)(7+27)*18 \\ =(1)/(2)*34*18 \\ =306\text{ sq. units} \end{gathered}`

Area of the trapezoid to the right:

`\begin{gathered} \text{Area}=(1)/(2)(a+b)** h \\ =(1)/(2)(13+27)*12 \\ \text{Area}=(1)/(2)*40*12 \\ =240\text{ sq. units} \end{gathered}`

Therefore, the area of the region is calculated by:

`\begin{gathered} \text{Area of region=Area of left trapezoid + Area of right trapezoid} \\ =(306+240)\text{ sq. units} \\ =546\text{ sq. units} \end{gathered}`

The answer is 546 sq. units [Option B]