Question

Solve for x to the nearest tenth.ln (x + 1) = 7

Answer 1

Given that

`\ln (x+1)=7`

To solve for x, applying log rules

Where

`\begin{gathered} \ln N=x \\ N=e^x \end{gathered}`

Applying the log rule above to the given expression

`\begin{gathered} \ln (x+1)=7 \\ e^(\ln (x+1))=e^7 \\ x+1=e^7 \end{gathered}`

Solve for x, i.e make x the subject

`\begin{gathered} x+1=e^7 \\ x=e^7-1 \\ x=1096.63316-1 \\ x=1095.63316 \\ x=1095.6\text{ (nearest tenth)} \end{gathered}`

Hence, x = 1095.6 (nearest tenth)