Question

Turn the word equations into chemical formulas.1 Sulfur solid reacts with iron solid to form solid iron(III) sulfide.2. Hydrogen gas and iron(III) oxide powder react to form liquid water and solid iron powder.3. Magnesium metal reacts with hydrochloric acid to form magnesium chloride solution and hydrogen gas.4. Magnesium sulfide solid and hydrochloric acid react to form hydrogen sulfide gas and magnesium chloride solution.5. Oxygen gas reacts with solid copper metal to form copper(II) oxide solid.

Answer 1

Reaction 1

Solid sulfur can be represented by S(s) and solid iron is represented by Fe(s). Note the little s stands for solid.

Iron(III) sulfide will have the following formula:

`Fe^(3+)+S^(2-)\rightarrow Fe_2S_3`

Reaction 2

Hyrogen gas can be represented by H2(g) and Iron (III) Oxide will have the following formula:

`Fe^(3+)+O^(2-)\rightarrow Fe_2O_3`

The products are H2O(l) and Fe(s). Therefore:

`H_(2(g))+Fe_2O_(3(g))\rightarrow H_2O_((l))+Fe_((s))`

Reaction 3

Magnesium metal can be representd as Mg(s) and hydrochloric acid is HCl. Magnesium chloride will have the following formula:

`Mg^(2+)+Cl^-\rightarrow MgCl_2`

Therefore, the equation can be writen as:

`Mg_((s))+HCl_((aq))\rightarrow MgCl_(2(aq))+H_(2(g))`

Reaction 4

Magnesium sulfide has the following formula:

`Mg^(2+)+S^(2-)\rightarrow MgS`

The reaction can be writen thus as:

`MgS_((s))+HCl_((aq))\rightarrow H_2S_((g))+MgCl_(2(aq))`

Reaction 5

Oxygen gas can be represented as O2(g) and solid copper as Cu(s). Copper (II) oxide has the following formula:

`Cu^(2+)+O^(2-)\rightarrow CuO`

The reaction can be writen thus as:

`O_(2(g))+Cu_((s))\rightarrow CuO_((s))`