1 Answer

Satake · Answer 1 · 2022-07-01T06:52:16+0000

Answer: Thus empirical and molecular formula is sa,e for

Step-by-step explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

1. The empirical formula is
CO_2H

The empirical weight of
CO_2H = 1(12)+2(16)+1(1)= 45g.

The molecular weight = 90 g/mole

Now we have to calculate the molecular formula:

$n=\frac{\text{Molecular weight }{\text{Equivalent weight}=(90)/(45)=2$

The molecular formula will be=
2* CO_2H=C_2O_4H_2

2. The empirical formula is
CH_3O

The empirical weight of
CH_3O = 1(12)+3(1)+1(16)= 31 g.

The molecular weight = 62 g/mole

Now we have to calculate the molecular formula:

$n=\frac{\text{Molecular weight }{\text{Equivalent weight}=(62)/(31)=2$

The molecular formula will be=
2* CH_3O=C_2H_6O_2

3. The empirical formula is
C_2H_4O

The empirical weight of
C_2H_4O = 2(12)+4(1)+1(16)= 44 g.

The molecular weight = 88 g/mole

Now we have to calculate the molecular formula:

$n=\frac{\text{Molecular weight }{\text{Equivalent weight}=(88)/(44)=2$

The molecular formula will be=
2* C_2H_4O=C_4H_8O_2

4. The empirical formula is
C_4H_8O

The empirical weight of
C_4H_8O = 4(12)+8(1)+1(16)= 72 g.

The molecular weight = 72 g/mole

Now we have to calculate the molecular formula:

$n=\frac{\text{Molecular weight }{\text{Equivalent weight}=(72)/(72)=1$

The molecular formula will be=
1* C_4H_8O=C_4H_8O

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