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2/5 (z+ 1) = y for z

User Jeff Day
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(2)/(5)(_{}z+1)=y
\begin{gathered} \text{Distributive property:} \\ (2)/(5)z+(2)/(5)=y \\ \\ \text{Subtract 2/5 in both sides of the equation:} \\ (2)/(5)z+(2)/(5)-(2)/(5)=y-(2)/(5) \\ \\ (2)/(5)z=y-(2)/(5) \\ \\ \text{Multiply both sides of the equation by 5/2} \\ (5)/(2)\cdot(2)/(5)z=(5)/(2)(y-(2)/(5)) \\ \\ z=(5)/(2)y-(10)/(10) \\ \\ z=(5)/(2)y-1 \end{gathered}

User Alexloh
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