Question

An astronaut on the planet Zircon tosses a rock horizontally with a speed of 6.95m/s. The rock falls through a vertical distance of 1.40m and lands a horizontal distance of 8.75m from the astronaut. What is the acceleration of gravity on Zircon?

Answer 1

`\begin{gathered} v_x=6.95\text{ m/s} \\ x=8.75m \\ y=1.40m \\ t=\text{?} \\ g=\text{?} \\ To\text{ find t} \\ v_x=(x)/(t) \\ \text{Solving t} \\ t=(x)/(v_x) \\ t=\frac{8.75m}{6.95\text{ m/s}} \\ t=1.30s \\ To\text{ find g} \\ y=(gt^2)/(2) \\ \text{Solving g} \\ 2y=gt^2 \\ g=(2y)/(t^2) \\ g=(2(1.40m))/((1.30s)^2) \\ g=1.7m/s^2 \\ \text{The gravity }on\text{ Zicron is }1.7m/s^2 \end{gathered}`