Question

How many molecules of H20 areequivalent to 97.2 g H20?(H = 1.008 g/mol, O = 16.00 g/mol)[ ? ]x10! ?! moleculesEnter your answer with the correct number ofsignificant figures and be sure the prefix is a numberbetween 1 and 10!Hint: Avogadro's Number = 6.02 x 1023 molecules/molePrefix (green) Exponent (yellow)Enter

Answer 1

3.25 x 10²⁴ molecules

Step-by-step explanation

Given:

Mass of H₂O = 97.2 g

Atomic mass: (H = 1.008 g/mol, O = 16.00 g/mol)

Avogadro's Number = 6.02 x 10²³ molecules/mole

What to find:

The number of molecules of H₂O equivalent to 97.2 g H₂O.

Step-by-step solution:

The first step is to determine the number of moles of H₂O in 97.2 g H₂O.

Let x represents the number of moles in 97.2 g H₂O

1 mole of water is equivalent to (2 x 1.008 g + 16.00 g) = 18.016 g of H₂O

So x mole of water is equivalent to 97.2 g of H₂O

Cross multiply

(1 mole x 97.2 g) = x mole x 18.016 g

Divide both sides by 18.016 g

`x=\frac{1\text{ mole }*97.2\text{ g}}{18.016\text{ g}}=5.395204263\text{ moles}`

Hence, 5.395204263 moles of H₂O are equivalent to 97.2 g of H₂O.

The final step is to determine the number of molecules in 5.395204263 moles of H₂O.

`\begin{gathered} 1\text{ mole }=6.02*10^(23)\text{ molecules} \\ 5.395204263\text{ moles }=5.395204263*6.02*10^(23)=3.25*10^(24)\text{ molecules} \end{gathered}`

Therefore, there