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What is the area of this rombus. use picture for reference

What is the area of this rombus. use picture for reference-example-1

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We are given a rhombus with one side measuring 5 cm, and one angle measuring 50 degrees. To determine the area we can use the following formula:


A=a^2sin\alpha

Where "a" is one side and alpha is the measure of any interior angle of the rhombus. In this case, we have that


\angle\text{ODC}=50^0

Since line DB bisects the angle ADC, that means that:


\angle ADC=2(50^0)=100^0

Replacing in the formula for the area:


A=(5\operatorname{cm})^2\sin 100

Solving we get:


A=24.62cm^2

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