1 Answer

Luiza · Answer 1 · 2023-12-29T16:27:36+0000

We are given a rhombus with one side measuring 5 cm, and one angle measuring 50 degrees. To determine the area we can use the following formula:

$A=a^2sin\alpha$

Where "a" is one side and alpha is the measure of any interior angle of the rhombus. In this case, we have that

$\angle\text{ODC}=50^0$

Since line DB bisects the angle ADC, that means that:

$\angle ADC=2(50^0)=100^0$

Replacing in the formula for the area:

$A=(5\operatorname{cm})^2\sin 100$

Solving we get:

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