Question

HELP PLEASE AND NO LINKS!!!!!!

The length of a rectangle is twice its width. Given the length of the diagonal is $5\sqrt{5}$, find the area of the rectangle.

Answer 1

Explanation:

Width =x

Length = 2*x = 2x

Diagonal = 5√5

Use Pythagorean theorem

Length² + Width² = diagonal²

(2x)² + x² = (5√5)²

{
`(5√(5))^(2)=5√(5) *5√(5)=5*5*√(5*5)=25*5=75`}

4x² + x² = 75

5x² = 75

x² = 75/5

x² = 15

x = √15

Width = √15

Length = 2√15

Area of rectangle = length *width

= √15 *2√15

`= 2* √(15*15)\\\\= 2*15\\= 30`

= 30 square units