Question

Regular pentagon ABCDEF in circle P. What is the measure of

Answer 1

The sum of angles in a pentagon is 540°. This means that for a regular pentagon, each angle is given as

`(540)/(5)=108^(\circ)`

Observe ΔABC,

ΔABC is an isosceles triangle given lines AB and BC are equal sides of the regular pentagon.

Therefore, summing up the angles in ΔABC,

[tex]\begin{gathered} But

Thus,

Inputting value of

108 + 2(2