Question

AgNO3 solutions are often used to plate silver onto other metals. What is the maximum amount of silver in grams that can be plated out of 4.8 L of an AgNO3 solution containing 3.4 Ag by mass? ( Assume that the density of the solution is 1.01 g/mL)

Answer 1

In this question, we have to find the maximum amount of grams that can be plated, and the informations we have are:

AgNO3

4.8 L of AgNO3 solution

3.4% of Ag by mass

density = 1.01g/mL

Using density and the volume of the solution, we can find the total mass of the solution, using the density formula:

d = m/v

d is going to be 1.01g/mL

m = ?

v = it will be 4800 mL, since we need mL and we have 4.8 L

Adding these values to the formula

1.01 = m/4800

m = 4848 grams

Now, since we have only 3.4% of Ag, we use the value in grams of the total solution to find the final mass of Ag

4848 g = 100%

x grams = 3.4%

x = 164.832 grams of Ag is the maximum amount.