Question

HELPPPPP !!!!

A projectile is at 12.5 m/s at an angle of 53.1° with the horizontal from a point 75.0 m above the ground.

a) How long does it take to reach the ground?

b) What maximum height does it reach?

c) What horizontal distance does it travel before striking the ground?

d) With what velocity does it strike the ground?

I just need the work to show

Answer 1

Your answer is C)

a)t=2.78 sec

b)R=835.03 m

c)

Step-by-step explanation:

Given that

h= 38 m

u=300 m/s

here given that

The finally y=0

So

t=2.78 sec

The horizontal distance,R

R= u x t

R=300 x 2.78

R=835.03 m

The vertical component of velocity before the strike