Let x be the number of napkins Carla organized in 1 hour, and y be the number of napkins Karen organized in 1 hour, then we can set the following system of equations:
![\begin{gathered} 3x+3y=90, \\ x=3y\text{.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ilj28qzrezkgsz6r85pozbxlv9gg44kbar.png)
Substituting x=3y in the first equation we get:
![3(3y)+3y=90.](https://img.qammunity.org/2023/formulas/mathematics/college/813727tqim1oifwcny0tkcejqsdoj0pkvd.png)
Solving for y we get:
![\begin{gathered} 9y+3y=90, \\ 12y=90, \\ y=(90)/(12), \\ y=7.5. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/u96xlxtdydjd5wtettjh5kuxxhb3kl711d.png)
Therefore, Karen organized 7.5 napkins each hour and Carla organized 7.5x3=22.5 napkins each hour.
Answer: Since Karen organized 7.5 napkins each hour, then it would take her
![(90)/(7.5)=12](https://img.qammunity.org/2023/formulas/mathematics/college/agsa4fw3dtjl5daxhso5is5fhvxfx0urcb.png)
hours to do the 90 napkins.
Since Carla organized 22.5 napkins each hour, it would take her
![(90)/(22.5)=4](https://img.qammunity.org/2023/formulas/mathematics/college/85lcn5ij39ol0ex7hgz6nrzn2mzsqdx0c8.png)
hours to do the 90 napkins.