Question

Please help with this. This is the fourth Tudor please help

Answer 1

The zeros of graph are;

`x\text{ = 0, x=2 and x = 2}`

It is x = 2 twice because at x = 2, it is a turning point of a curve.

`\begin{gathered} x\text{ = 0, x = 2, x = 2} \\ x\text{ = 0, x - 2 = 0, x - 2 = 0} \\ x\text{ (x-2) (x-2) = 0} \end{gathered}`

We now want to expand;

`\begin{gathered} x(x^2-2x-2x+4)=0\text{ } \\ x(x^2\text{ - 4x + 4 ) = 0} \\ x^3-4x^2\text{ + 4x = 0} \\ f(x)=x^3-4x^2\text{ + 4x} \end{gathered}`