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Solve using substitution.5x + 4y = -12x = -8

User Adamency
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1 Answer

4 votes

Let:


\begin{gathered} 5x+4y=-12_{\text{ }}(1) \\ x=-8_{\text{ }}(2) \end{gathered}

Replace (2) into (1):


\begin{gathered} 5(-8)+4y=-12 \\ -40+4y=-12 \\ solve_{\text{ }}for_{\text{ }}y\colon \\ 4y=40-12 \\ 4y=28 \\ y=(28)/(4) \\ y=7 \end{gathered}

So:

x = -8

y = 7

User Zabulus
by
8.1k points

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