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(5,-10)(-9,10) what is the linear equation

User Achim
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1 Answer

5 votes

In order to find the linear equation, let's use the slope-intercept form below:


y=mx+b

Where m is the slope and b is the y-intercept.

Now, using the points (5, -10) and (-9, 10), we have:


\begin{gathered} y=mx+b \\ (5,-10)\colon \\ -10=5m+b \\ (-9,10)\colon \\ 10=-9m+b \end{gathered}

Subtracting one equation by the other, we have:


\begin{gathered} -10-(10)=5m+b-(-9m+b) \\ -10-10=5m+b+9m-b \\ -20=14m \\ m=-(20)/(14)=-(10)/(7) \\ \\ -10=5m+b \\ -10=-(50)/(7)+b \\ b=-10+(50)/(7) \\ b=-(20)/(7) \end{gathered}

So our linear equation is:


y=-(10)/(7)x-(20)/(7)

User Sadjad
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