Answer:
The amount in the account after 3 years is $672.00
Explanation:
Here, we want to use the compound interest formula
A = P(1 + r/n)^nt
A is the amount in the account after the given time
P is the principal which is the deposit amount = $600
r is the interest rate = 3.85% = 3.85/100 = 0.0385
n is the number of times interest is compounded yearly (since it is annually, n = 1)
t is the time in years = 3
Substituting these values;
A = 600(1 + 0.0385/1)^(3 * 1)
A = 600(1.0385)^3
A = $672