We have to find the equation of the line in standard form, knowing that the slope is m = -5 and it passes through the point (2, 1).
The standard form is:
![Ax+By=C](https://img.qammunity.org/2023/formulas/mathematics/high-school/75j0pzqy8f6gtpgzjampxw030qc85p0hp7.png)
When we know the slope and one point, we can write the equation in slope-point form. Then, we can rearrange the terms in order to find the standard form.
The slope-point form is:
![\begin{gathered} y-y_0=m(x-x_0) \\ y-1=-5(x-2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2iocekcebtzc3rs47emopbtixhceth47z0.png)
We then can rearrange it as:
![\begin{gathered} y-1=-5(x-2) \\ y=-5x-5\cdot(-2)+1 \\ y=-5x+10+1 \\ y+5x=11 \\ 5x+y=11 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/w58ykqhvtf2l7p4ease8o50wk22evhgjjk.png)
Answer: the standard form of the line is 5x + y = 11.