Okay, here we have this:
Considering the provided information, we are going to calculate the volume of the cone, so we obtain the following:
We will substitute in the following formula for the volume of a cone:
![V=(1)/(3)\pi R^2h](https://img.qammunity.org/2023/formulas/mathematics/college/r85zoyhi3wac13ytpxwmil4vjmvliawpch.png)
Replacing we obtain:
![\begin{gathered} V=(1)/(3)\pi(11yd)^2\cdot(15yd) \\ V=(1)/(3)\pi121yd^2\cdot15yd \\ V=5yd\cdot121yd^2\cdot\pi \\ V=605\pi yd^3 \\ V=605(3.14)yd^3 \\ V=1899.7yd^3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/omtvd75lmm4sknwyd4pjv69kdt5zaq5bhg.png)
Finally we obtain that the volume of the cone is approximately 1899.7yd^3.