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What is the distance from A to B given

User Ohm
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1 Answer

2 votes

Using the triangle sum theorem, we can conclude:


\begin{gathered} m\angle A+m\angle B+m\angle C=180 \\ 40+m\angle B+50=180 \\ so\colon \\ m\angle B=180-50-40 \\ m\angle B=180-90 \\ m\angle B=90 \end{gathered}

Now, we can use the law of sines in order to find AB:


\begin{gathered} (AB)/(\sin(C))=(AC)/(\sin (B)) \\ solve_{\text{ }}for_{\text{ }}AB\colon_{} \\ AB=(\sin (C)\cdot AC)/(\sin (B)) \\ AB=(\sin (50)\cdot100)/(\sin (90)) \\ AB=76.60444431ft \end{gathered}

User Burakk
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