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What is the 13 term of the sequence 2,6,18,54

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Notice that:


\begin{gathered} 2=2*3^0, \\ 6=2*3^1, \\ 18=2*3^2, \\ 54=2*3^3. \end{gathered}

Therefore, the rule to compute the nth term of the sequence is:


a_n=2*3^(n-1).

Substituting n=13 in the above equation we get:


a_(13)=2*3^(13-1)=2*3^(12)=1062882.

Answer: 1062882.

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