Question

How does g(t) = 1/2t change over the interval t = 0 to t = 1?

Answer 1

we have the equation

`g(t)=(1)/(3^t)`

Find out the rate of change over the interval [0,1]

Remember that

the formula to calculate the rate of change is equal to

`(g(b)-g(a))/(b-a)`

In this problem

a=0

b=1

g(a)=g(0)=1

g(b)=g(1)=1/3

therefore

the function decreases by a factor of 3