Question

Can anyone help me this please this is my last question to pass

Answer 1

Lets take 2 pair of points from the table:

`\begin{gathered} (x_1,y_1)=(0,4) \\ (x_2,y_2)=(2,10) \end{gathered}`

The equation of line is y = mx + b

Where

m is slope

b is y-intercept

Let's find the slope (m):

`\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=(10-4)/(2-0) \\ m=(6)/(2) \\ m=3 \end{gathered}`

So, the equation becomes:

`y=3x+b`

Let's plug in the first point (x, y) = (0,4) to find b:

`\begin{gathered} y=3x+b \\ 4=3(0)+b \\ 4=0+b \\ b=4 \end{gathered}`

Final Equation of the line:

`y=3x+4`