We want to solve
2x^2–9=11
First, isolate the portion of the equation that's actually being squared. That is:
2x^2 = 11 + 9
that is equivalent to:
2x^2 = 20
that is equivalent to
x^2 = 20/ 2 = 10
that is
x^2 = 10
Now square root both sides and simplify, that is:
![\sqrt[]{x^2\text{ }}=\text{ }\sqrt[]{10}](https://img.qammunity.org/2023/formulas/mathematics/college/ja2r593amy8p91ljahk42tl5cw5ib3p0pr.png)
we know that the square root is the inverse function of the function x^ 2, so we can cancel the square :
![x\text{ = }\sqrt[]{10}](https://img.qammunity.org/2023/formulas/mathematics/college/nmy2fyj18azvankafonff3ad82d16kf44d.png)
but note that there is always the possibility of two roots for every square root: one positive and one negative: so the final answer is:
![x\text{ = +/- }\sqrt[]{10}](https://img.qammunity.org/2023/formulas/mathematics/college/12kjcl8r644bkpku5ceb8s8klb3muvpfwr.png)