Question

The Taipei Tower is a 508 meter, 101 story skyscraper. If you were to toss a orange of 0.13 kg off the top, how much kinetic energy would it have when it hits the sidewalk? Ignore air resistance .

Answer 1

647.19 J

Step-by-step explanation:

By the conservation of energy, the potential energy when you toss the orange is converted to kinetic energy when it hits the sidewalk, so

Ef = Ei

KE = PE

KE = mgh

Where m is the mass, g is 9.8 m/s², and h is the height of the Tower. Replacing m by 0.13 kg and h by 508 meters, we get

KE = (0.13kg)(9.8 m/s²)(508 m)

KE = 647.19 J

So, the orange would have 647.19 J of kinetic energy when it hits the sidewalk.