Question

Triangle ABC shown below has m B = 38°, a = 8, and c = 16. Find the area of the triangle. Round your answer to the nearest tenth and do not include units in your answer.

Answer 1

The area of triangle is determined as

`A=(1)/(2)a* c*\sin B`
`A=(1)/(2)*8*16*\sin 38=64\sin 38^(\circ)`
`A=39.4\text{ squnit}`

Thus the area of triangle is 39.4 sq.unit.