Given
Original cans
Height of 6 inches
Diameter of 4 inches
New boxes
2 inches deep
4 inches wide
Same volume
Procedure
Now let's calculate the volume of the soup cans.
![\begin{gathered} V=\pi r^2h \\ V=\pi(2)^2(6) \\ V=75.36\text{ cubic inches} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qis9sksjtxj4t5msg6qulz0ot6prwpe236.png)
Now let's calculate the volume of the boxes
![\begin{gathered} V=2\cdot4\cdot h \\ V=8h \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qiy62v2q2ec19jt1sxyepkj0cjxwlj7tkz.png)
Now we must equal the volume of the cans and then calculate the height.
![\begin{gathered} 75.36=8h \\ h=(75.36)/(8) \\ h=9.42\text{ inches} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/os1k09yi8q8qyu6y2m40to9koxlh3eaoq6.png)
The height of the boxes must be equal to 9.42 inches.