Question

Lead ions can be removed from solution by precipitation with sulfate ions. Suppose a solution contains lead(II) nitrate.

Answer 1

1) List the compounds involved in the reaction.

Lead (II) nitrate

Potassium sulfate

Lead (II) sulfate

Potassium nitrate.

2) Write the formula of every compound.

Lead (II) nitrate: Pg(NO3)2

Potassium sulfate: K2SO4

Lead (II) sulfate: PbSO4

Potassium nitrate: KNO3

3) Write the chemical equation

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`Pb(NO_3)_2+K_2SO_4\rightarrow PbSO_4+KNO_3`

List the elements (or polyatomic ions) in the reactants.

Pb: 1

NO3: 2

K: 2

SO4: 1

List the elements (or polyatomic ions) in the products.

Pb: 1

NO3: 1

K: 1

SO4: 1

Balance K.

`Pb(NO_3)_2+K_2SO_4\rightarrow PbSO_4+2KNO_3`

List the elements (or polyatomic ions) in the reactants.

Pb: 1

NO3: 2

K: 2

SO4: 1

List the elements (or polyatomic ions) in the products.

Pb: 1

NO3: 2

K: 2

SO4: 1

4) Balanced chemical equation.

`Pb(NO_3)_(2(aq))+K_2SO_(4(aq))\rightarrow PbSO_(4(s))+2KNO_(3(aq))`

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