Question

Given the dot product w•w = 29, find the magnitude of w.

Answer 1

Option D is correct.

`|w|=√(29)`

Explanations:

Given the dot product expression as shown:

`w\cdot w=29`

Determine the value of 'w"

`w^2=29`

Take the square root of both sides to have:

`\begin{gathered} √(w^2)=\pm√(29) \\ w=\pm√(29) \end{gathered}`

Since we only need the magnitude of "w" and the magnitude is the positive value of the variable, hence;

`|w|=√(29)`

This gives the modulus of "w"