92.4k views
3 votes
Romeo and Juliet are sitting on a balcony 1.5 meters apart. If Romeo has a mass of 61.6 Kg and Juliet has a mass of 48.8 kg. What is the attractive force between them?

User Arninja
by
5.8k points

1 Answer

5 votes

\begin{gathered} m_(Romeo)=61.6\text{ kg} \\ m_(Juliet)=48.8\text{ kg} \\ r=1.5\text{ m} \\ G=6.673x10^(-11)Nm^2/kg^2 \\ F=G*(m_(Juliet)m_(Romeo))/(r^2) \\ \\ F=\left(6.673x10^(-11)Nm^2/kg^2\right)\frac{\left(48.8\text{ kg}\right)\left(61.6\text{ kg}\right)}{\left(1.5\text{ m}\right)^2} \\ \\ F=8.91x10^(-8)N \\ The\text{ attractive force is 8.91x10}^(-8)\text{N} \end{gathered}

User Gareth Ma
by
5.2k points