Question

What mass of sodium hydroxide is needed to neutralise 24.5kg of sulfuric acid

H2SO4 + N2 = 2NH3

Answer 1

20g

Step-by-step explanation:

First of all, you have got your formula wrong. It should be
`H_(2)SO_(4) + 2NaOH = Na_(2)SO_(4) + 2H_(2)O`.

Start by finding the Relative Formula Mass for sulfuric acid.
`H_(2)SO_(4)` is equal to (2x1)+32+(16x4)=98. You then calculate Mols by doing
`Mols=(Mass)/(Relative Formula Mass)`. So,
`(24.5)/(98) = 0.25`, so the Mols of Sulfuric Acid is 0.25.

The Mol ratio of Sulfuric Acid to Sodium Hydroxide is 1:2, so 0.25:0.5.

Now, you have to find the Relative Formula Mass of Sodium Hydroxide, or
`NaOH`. 23+16+1=40. Finally, multiply 0.5 by 40, and you'll find that the maximum mass is 20g.